*Author/s: Makbule Gozde Didis, Ayhan Kursat Erbas DOI: 10.12738/estp.2015.4.2743 Year: 2015 Vol: 15 Number: 4 Abstract This study attempts to investigate the performance of tenth-grade students in solving quadratic equations with one unknown, using symbolic equation and word-problem representations.*

Based on this can you find a discrepancy between your approach and mine?

Baring errors does mine match your expected result?

A second method of solving quadratic equations involves the use of the following formula: , b is the numeral that goes in front of x, and c is the numeral with no variable next to it (a.k.a., “the constant”).

When using the quadratic formula, you should be aware of three possibilities.

Thus, it is concluded that the differences in the structural properties of the symbolic equations and word problem representations affected student performance in formulating and solving quadratic equations with one unknown.

## Using Quadratic Equations To Solve Word Problems

Stack Exchange network consists of 175 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. How much time does individual pedestrian need in order to walk 1km of path, if the first pedestrians walks this path of 1km one minute less than the other pedestrian? The second one takes $\frac v-1$ minutes to walk

Stack Exchange network consists of 175 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. How much time does individual pedestrian need in order to walk 1km of path, if the first pedestrians walks this path of 1km one minute less than the other pedestrian? The second one takes $\frac v-1$ minutes to walk $1$ km. We then get $$76=6v 6\cdot \frac $$ Using the formula $t=d/v$, you can write down two equations from the statements in the problem.

Student difficulties in solving symbolic problems were mainly associated with arithmetic and algebraic manipulation errors.

In the word problems, however, students had difficulties comprehending the context and were therefore unable to formulate the equation to be solved.

I am answering because I do not have comment ability yet. Here is the problem, are you trying to get time or rate? d1 d2 = 76km d1 = v1*T d2 = v2*T T = 6h = 360min v1 = 1km/t v2 = 1km/(t-1min) Putting together...

1/t 1/(t-1min) = 76/360 This leads to 19*t^2 - 180*t 71 = 0 (steps suppressed) The answer is ~9.06 min, the other is less than half a min.

||Stack Exchange network consists of 175 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. How much time does individual pedestrian need in order to walk 1km of path, if the first pedestrians walks this path of 1km one minute less than the other pedestrian? The second one takes $\frac v-1$ minutes to walk $1$ km. We then get $$76=6v 6\cdot \frac $$ Using the formula $t=d/v$, you can write down two equations from the statements in the problem.Student difficulties in solving symbolic problems were mainly associated with arithmetic and algebraic manipulation errors.In the word problems, however, students had difficulties comprehending the context and were therefore unable to formulate the equation to be solved.I am answering because I do not have comment ability yet. Here is the problem, are you trying to get time or rate? d1 d2 = 76km d1 = v1*T d2 = v2*T T = 6h = 360min v1 = 1km/t v2 = 1km/(t-1min) Putting together...1/t 1/(t-1min) = 76/360 This leads to 19*t^2 - 180*t 71 = 0 (steps suppressed) The answer is ~9.06 min, the other is less than half a min.Of course you want to ensure you have a solid understanding of solving quadratic equations before watching this lesson.Like all word problems in math, there is no one single procedure you can use to solve a problem.When studying how to solve word problems we focus on general steps and approaches that will help you organize and solve the problem.After you watch the lesson the most important thing to do is practice, practice, practice.These three possibilities are distinguished by a part of the formula called the discriminant.The discriminant is the value under the radical sign, b – 4 ac is 0, the equation has one root.

$ km. We then get $=6v 6\cdot \frac $$ Using the formula $t=d/v$, you can write down two equations from the statements in the problem.Student difficulties in solving symbolic problems were mainly associated with arithmetic and algebraic manipulation errors.

In the word problems, however, students had difficulties comprehending the context and were therefore unable to formulate the equation to be solved.

I am answering because I do not have comment ability yet. Here is the problem, are you trying to get time or rate? d1 d2 = 76km d1 = v1*T d2 = v2*T T = 6h = 360min v1 = 1km/t v2 = 1km/(t-1min) Putting together...

1/t 1/(t-1min) = 76/360 This leads to 19*t^2 - 180*t 71 = 0 (steps suppressed) The answer is ~9.06 min, the other is less than half a min.

## Comments Using Quadratic Equations To Solve Word Problems

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Your v−160 for the slower one is incorrect. You are measuring v in km/hour. If the first one walks v km/hour, he takes 60v minutes to walk 1 km.…